• Recently updated for the latest Force Unit Test (unit 2).
     
     
     
     
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     Further explanation of #6:
    The Vertical component of the force will end up REDUCING the Normal Force due to the equation Fn = Fg - Fvert.
    The vertical force should be 289.2544N. This subtracted from the weight of 852.6N (found using Fg = m*g), and results in a Fn of 563.3455N. This is important because Friction is found using the equation Ff = u * Fn. Using the normal force, multiplied by the coefficient of 0.35, the friction force is determined to be 197.1709N. To find the net force this is subtracted from the Horizontal component of 344.7199N, resulting in a Fnet of 147.5490N to the right (at least based on how I drew it). 
     
    WARNING: Number 9 is incorrect. I used 0.2 for some reason. The correct answer should be 90.16 N.
     
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    WARNING: Number 9 is incorrect. I used 0.2 for some reason. The correct answer should be 90.16 N. 
     
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    smell dat fresh lawn @gunthergsd